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  1. # your code goes here
  2. n=int(input())
  3. a=list(map(int, input().split()))
  4. minFreq=n+1
  5. maxFreq=0
  6. minElem=-1
  7. maxElem=-1
  8. for i in range(n):
  9. 	count=0
  10. 	for j in range(n):
  11. 		if a[j]==a[i]:
  12. 			count+=1
  13. 	if count<minFreq:
  14. 		minFreq=count
  15. 		minElem=a[i]
  16. 	if count>maxFreq:
  17. 		maxFreq=count
  18. 		maxElem=a[i]
  19. print(minFreq, minElem)
  20. print(maxFreq, maxElem)
Success #stdin #stdout 0.07s 14196KB
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stdin
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5
1 1 2 2 3
stdout
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1 3
2 1
https://ideone.com/xkHE4B
Print the numbers which has maximum and minimum frequency
language:
Python 3 (python  3.12)
created:
1 day ago
visibility:
public

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