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  1. # include <stdio.h>
  2.  
  3. int isPalindrome(char s[]){
  4. 	int i,j,count=0;
  5. 	for(i=0;s[i]!='\0';i++){
  6. 		count++;
  7. 	}
  8. 	for(j=0;j<=count/2;j++){
  9. 		if(s[j]!=s[count-1-j])
  10. 		return 0;
  11. 	}
  12. 	return 1;
  13.  
  14. 	}
  15. 	//回文になっているとき１を返す
  16. 	//回文になっていないとき０を返す
  17.  
  18.  
  19. //メイン関数は書き換えなくてよいです
  20. int main(){
  21.     char s[100];
  22.     scanf("%s",s);
  23.     printf("%s -> %d\n",s,isPalindrome(s));
  24.     return 0;
  25. }
  26.  
Success #stdin #stdout 0s 5316KB
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girafarig
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https://ideone.com/lHjMXq
language:
C (gcc 8.3)
created:
8 hours ago
visibility:
public

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