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  1. /* Count the occurrences of a value in an array */
  2.  
  3. #include <stdio.h>
  4.  
  5. int main(void) 
  6. {
  7. 	int myarray[] = {4,9,7,6,6,6,6,2,1,5};
  8. 	int count = 0;
  9. 	int to_find = 6;
  10.  
  11. 	for (int i = 0; i < 10; i++){
  12. 		printf ("myarray[%d] = %d\n", 
  13. 				i, myarray[i]);
  14. 		if (myarray[i] == to_find){
  15. 			count++;
  16. 		printf (" found %d incremented count to %d\n",
  17. 				to_find, count);
  18. 		}
  19. 	}
  20. 		printf("# of 6s found is: %d\n", count);
  21.  
  22. 	return 0;
  23. }
Success #stdin #stdout 0.01s 5320KB
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stdin
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Standard input is empty
stdout
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myarray[0] = 4
myarray[1] = 9
myarray[2] = 7
myarray[3] = 6
 found 6 incremented count to 1
myarray[4] = 6
 found 6 incremented count to 2
myarray[5] = 6
 found 6 incremented count to 3
myarray[6] = 6
 found 6 incremented count to 4
myarray[7] = 2
myarray[8] = 1
myarray[9] = 5
# of 6s found is: 4
https://ideone.com/iHi2ZW
language:
C++ (gcc 8.3)
created:
1 hour ago
visibility:
public

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