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  1. nums = [5, 12, 7, 9, 21, 7, 14]
  2. count_seven = nums.count(7)
  3. print("数字7出现的次数：", count_seven)
  4. if 99 not in nums:
  5.     nums.append(99)
  6. print("添加99后的列表:",nums)
  7. nums.remove(7)
  8. print("删除第一个7后的列表",nums)
  9. sublist=nums[1:4]
  10. print("第2-4元素组成的列表",sublist)
Success #stdin #stdout 0.08s 14156KB
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数字7出现的次数： 2
添加99后的列表: [5, 12, 7, 9, 21, 7, 14, 99]
删除第一个7后的列表 [5, 12, 9, 21, 7, 14, 99]
第2-4元素组成的列表 [12, 9, 21]
https://ideone.com/eW1Jqp
language:
Python 3 (python  3.12)
created:
10 hours ago
visibility:
public

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