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  1. # include <stdio.h>
  2.  
  3. int isPalindrome(char s[]){
  4. 	//関数の中だけを書き換えてください
  5. 	//回文になっているとき１を返す
  6. 	//回文になっていないとき０を返す
  7. 	int i;
  8. 	for(i=0;s[i]!='\0';i++){
  9. 	}
  10.  
  11. 	for(int j=0;j<=(i-1)/2;j++){
  12. 		if(s[j]!=s[i-1-j]){
  13. 			return 0;
  14. 		}
  15. 	}
  16. 	return 1;
  17. }
  18.  
  19.  
  20. int main(){
  21.     char s[100];
  22.     scanf("%s",s);
  23.     printf("%s -> %d\n",s,isPalindrome(s));
  24.     return 0;
  25. }
  26.  
Success #stdin #stdout 0s 5324KB
comments (?)
stdin
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abba
stdout
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abba -> 1
https://ideone.com/Szx1wp
language:
C (gcc 8.3)
created:
2 days ago
visibility:
public

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