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  1. #include <stdio.h>
  2.  
  3. int rec(int n) {
  4.     if (n == 0) return 3;
  5.     if (n == 1) return 0;
  6.     if (n == 2) return 2;
  7.     return rec(n - 2) + rec(n - 3);
  8. }
  9.  
  10. int main(void) {
  11.     printf("anがnで割り切れるときのnの値:\n");
  12.  
  13.     for (int n = 1; n <= 50; n++) {
  14.         int an = rec(n);
  15.  
  16.         if (an % n == 0) {
  17.             printf("n = %d  (a%d = %d)\n", n, n, an);
  18.         }
  19.     }
  20.     return 0;
  21. }
  22.  
Success #stdin #stdout 0.01s 5316KB
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stdin
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Standard input is empty
stdout
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anがnで割り切れるときのnの値:
n = 1  (a1 = 0)
n = 2  (a2 = 2)
n = 3  (a3 = 3)
n = 5  (a5 = 5)
n = 7  (a7 = 7)
n = 11  (a11 = 22)
n = 13  (a13 = 39)
n = 17  (a17 = 119)
n = 19  (a19 = 209)
n = 23  (a23 = 644)
n = 29  (a29 = 3480)
n = 31  (a31 = 6107)
n = 37  (a37 = 33004)
n = 41  (a41 = 101639)
n = 43  (a43 = 178364)
n = 47  (a47 = 549289)
https://ideone.com/DYrWyD
language:
C (gcc 8.3)
created:
18 hours ago
visibility:
public

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